Two beakers contain acid and water in the ratio 2 : 3 and 3 : 4 respectively. If equal volumes of the mixtures from these two beakers are poured into a common beaker, find the resultant ratio of acid to water in the mixture in the common beaker.

29 : 41

Solution A,

Acid : Water

 2    :    3

Solution B,

Acid : Water

 3    :    4

⇒ Making quantities equal,

⇒ (2 : 3) x 7 = 14 : 21    and    (3 : 4) x 5 = 15 : 20

⇒ Adding both the ratio to make the resultant mixture = (14 + 15) : (21 + 20)

⇒ Acid : Water = 29 : 41.