Two beakers contain acid and water in the ratio 2 : 3 and 3 : 4 respectively. If equal volumes of the mixtures from these two beakers are poured into a common beaker, find the resultant ratio of acid to water in the mixture in the common beaker.
Answer & explanation
Correct answer: option 4
Solution A,
Acid : Water
2 : 3
Solution B,
Acid : Water
3 : 4
⇒ Making quantities equal,
⇒ (2 : 3) x 7 = 14 : 21 and (3 : 4) x 5 = 15 : 20
⇒ Adding both the ratio to make the resultant mixture = (14 + 15) : (21 + 20)
⇒ Acid : Water = 29 : 41.