If A is 28% more than B and C is 25% less than the sum of A and B, then by what percent will C be more than A?

33.6%

28% = \(\frac{7}{25}\)

              A          :       B     :      A+B   :    C

           (25+7)    :      25    

              32        :      25    →      57    :    57 × 75%   (ATQ)   

                A        :        C

               32       :    57 × 75%

               32       :    57 × \(\frac{3}{4}\)

              128       :   171

C is \(\frac{43}{128}\) × 100% ⇒ 33.6% more