Arrange the following in increasing number of quantum number when com…

The correct answer is Option (3) → A, B, C, D, E

Each spectral series of hydrogen is formed when the electron comes down from higher excited states to one fixed lower level \( n_f \). The series is named by this final quantum number.

    \( \text{A. Lyman Series: } n_f = 1 \)
    \( \text{B. Balmer Series: } n_f = 2 \)
    \( \text{C. Paschen Series: } n_f = 3 \)
    \( \text{D. Brackett Series: } n_f = 4 \)
    \( \text{E. Pfund Series: } n_f = 5 \)

In increasing order of the quantum number the order is A, B, C, D, E.

Note: A similar question was also asked in CUET (UG) 2023 on 06-06-2023 (Slot 1).

Note: This question is from the pre-rationalised NCERT book (2022-23). The topic was removed from the latest NCERT book (2026-27), but it is still in the CUET 2026 syllabus, so do not skip it.

NCERT (Pre-rationalised edition, 2022-23):
The Line Spectra of the Hydrogen Atom – “… For hydrogen spectrum, the Balmer formula corresponds to n_f = 2 and n_i = 3, 4, 5, etc. The results of the Bohr’s model suggested the presence of other series spectra for hydrogen atom–those corresponding to transitions resulting from n_f = 1 and n_i = 2, 3, etc.; n_f = 3 and n_i = 4, 5, etc., and so on. Such series were identified in the course of spectroscopic investigations and are known as the Lyman, Balmer, Paschen, Brackett, and Pfund series.”