The area enclosed between the curve y = ln (x + e) and the coordinate axes is :
Answer & explanation
Correct answer: option 1
Area = \(\int_{1-e}^{0} ln (x + e)dx\)
= \([x ln (x + e) - \int \frac{1}{x + e} dx]\)\(_0^1\)
= 1
The area enclosed between the curve y = ln (x + e) and the coordinate axes is :
Correct answer: option 1
Area = \(\int_{1-e}^{0} ln (x + e)dx\)
= \([x ln (x + e) - \int \frac{1}{x + e} dx]\)\(_0^1\)
= 1