If a and b are order and degree of differential equation \(y'' + (y')^2 + 2y = 0\), then value of 2a + 6b, is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 10
The highest derivative in the equation is y’’, so the order is a = 2.
The equation is a polynomial in the derivatives, and y’’ appears to the power 1, so the degree is b = 1. The square on y’ does not count, because the degree is the power of the highest-order derivative.
\(2a + 6b = 2(2) + 6(1)\)
\(= 4 + 6 = 10\)