The de Broglie wavelength of an electron, a proton, and a alpha particle are represented by $\lambda_e, \lambda_{p}, \lambda_\alpha$ respectively. If kinetic energy of electron, proton and alpha particle is same, then which of the following is correct.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\lambda_\alpha<\lambda_{p}<\lambda_{e}$
The mass of the particle (m) is -
$m_{electron}<m_{proton}<m_α$
and,
$λ∝\frac{1}{m}$
$∴\lambda_\alpha<\lambda_{p}<\lambda_{e}$