CUET Preparation Today
The de Broglie wavelength of an electron, a proton, and a alpha particle are represented by $\lambda_e, \lambda_{p}, \lambda_\alpha$ respectively. If kinetic energy of electron, proton and alpha particle is same, then which of the following is correct. |
$\lambda_{p}>\lambda_{e}>\lambda_\alpha$ $\lambda_\alpha<\lambda_{p}<\lambda_{e}$ $\lambda_\alpha<\lambda_e<\lambda_p$ $\lambda_{p}<\lambda_\alpha<\lambda_{e}$ |
$\lambda_\alpha<\lambda_{p}<\lambda_{e}$ |
The correct answer is Option (2) → $\lambda_\alpha<\lambda_{p}<\lambda_{e}$ |
