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What will come at place of x, (x < 10) for $\frac{(132÷12×x-3×3)}{(5^2-6×4+x^2)}=1$ ? |
2 4 3 1 |
1 |
$\frac{(132÷12×x-3×3)}{(5^2-6×4+x^2)}=1$ = 11x - 9 = 25 - 24 + x2 = 11x - 9 = 1 + x2 = x2 - 11x + 10 = 0 By solving the quadratic equation, x = 1 |
