A and B are mutually exclusive events with \(P(A)=\frac{2}{7}\) and \(P(B)=\frac{1}{3}\). What is the probability that A or B occurs?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(\frac{13}{21}\)
Mutually exclusive events cannot occur together, so P(A and B) \(=0\) and P(A or B) = P(A) + P(B).
P(A or B) \(\displaystyle =\frac{2}{7}+\frac{1}{3}=\frac{6}{21}+\frac{7}{21}=\frac{13}{21}\)