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Tap P can fill a cistern in 6 hours and tap Q can empty the cistern in 20 hours. If both taps are kept opened simultaneously, then the time taken by both to fill the cistern: |
\(\frac{60}{2}\) \(\frac{60}{7}\) \(\frac{50}{9}\) \(\frac{50}{6}\) |
\(\frac{60}{7}\) |
Total work = efficiency × time Total efficiency = 10 - 3 = 7 Both ( P + Q ) will take time → \(\frac{60}{7}\) = \(\frac{60}{7}\) hours |
