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If secθ + cosθ= 2, find the value of $sec^{55}θ+\frac{1}{sec^{55}θ}$. |
2 0 1 55 |
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secθ + cosθ= 2 cosθ + \(\frac{1}{cosθ }\) = 2 cos2θ+ 1 = 2cosθ on solving , cosθ = 1 So , θ = 0º Now , sec55θ + \(\frac{1}{sec55θ }\) put θ = 0º = sec550º + \(\frac{1}{sec550º }\) = 1 + 1 = 2
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