CUET Preparation Today
If the mean free path of atoms is doubled then the pressure of gas will become : |
P/4 P/2 P/8 P |
P/2 |
As \(\lambda = \frac{1}{\sqrt{2}} \frac{kT}{\pi d^2 P}\) \(\Rightarrow P \propto \frac{1}{\lambda}\) i.e. by increasing \(\lambda\) two times, pressure will become half. |
