CUET Preparation Today
How many reflexive relations are possible in a set $A$ whose $n(A) = 3$. |
$2^9$ $2^3$ $2^6$ $2^2$ |
$2^6$ |
The correct answer is Option (3) → $2^6$ ## Given, $n(A) = 3$ Total number of reflexive relations $= 2^{n(n-1)}$ $= 2^{3(3-1)} = 2^{3 \times 2} = 2^6$ |
