How many reflexive relations are possible in a set $A$ whose $n(A) = 3$.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $2^6$ ##
Given, $n(A) = 3$
Total number of reflexive relations $= 2^{n(n-1)}$
$= 2^{3(3-1)} = 2^{3 \times 2} = 2^6$