The basic character of the monoxides of the transition series is of the following order

TiO > VO > CrO > FeO

The correct answer is option 2. TiO > VO > CrO > FeO.

The basic character of oxides generally increases from left to right across the transition series. This is because the ability of an oxide to act as a base (i.e., accept protons) increases with increasing electronegativity of the metal cation. Based on this trend, the correct order for the basic character of monoxides of the transition series is: TiO > VO > CrO > FeO

TiO (Titanium(II) oxide): Titanium has a lower electronegativity compared to vanadium, chromium, and iron, making TiO the least basic among the given options.

VO (Vanadium(II) oxide): Vanadium has a higher electronegativity than titanium but lower than chromium and iron, making VO more basic than TiO but less basic than CrO and FeO.

CrO (Chromium(II) oxide): Chromium has a higher electronegativity than vanadium but lower than iron, making CrO more basic than TiO and VO but less basic than FeO.

FeO (Iron(II) oxide): Iron has the highest electronegativity among the given elements, making FeO the most basic oxide among the options provided.

Therefore, the correct order is TiO > VO > CrO > FeO.