CUET Preparation Today
The area enclosed between the curve $x^2+y^2 =16 $ and the coordinate axes in the first quadrant is : |
$12 \pi \, sq.units $ $8\pi \, sq.units $ $4\pi \, sq.units $ $2 \pi \, sq.units $ |
$4\pi \, sq.units $ |
The correct answer is option (3) → $4\pi$ sq.units area of curve in first quadrant ≡ area of quarter circle $=\frac{\pi ×4^2}{4}=4\pi$ sq. units |
