The area enclosed between the curve $x^2+y^2 =16 $ and the coordinate axes in the first quadrant is :
Answer & explanation
Correct answer: option 3
The correct answer is option (3) → $4\pi$ sq.units
area of curve in first quadrant
≡ area of quarter circle
$=\frac{\pi ×4^2}{4}=4\pi$ sq. units