The volume of a sphere is 8 times that of another sphere. What is the ratio of the surface area of the bigger sphere to that of the other?

4 : 1

As we know,

The volume of the sphere is the cube of its radius.

So,

\(\frac{V}{v}\) = \(\frac{RADIUS^3}{radius^3}\) 

\(\frac{8}{1}\) = \(\frac{RADIUS^3}{radius^3}\)

\(\frac{RADIUS}{radius}\) = \(\frac{2}{1}\)

Now the area of the spheres =

\(\frac{AREA}{area}\) = \(\frac{2^2}{1^2}\)  = \(\frac{4}{1}\)