If x4 + x2y2 + y4 = 273
x2 - xy + y2 = 13, then
find xy.
Answer & explanation
Correct answer: option 3
Formula → x4 + y4 + x2y2 = (x2 + y2 + xy) × (x2 + y2 - xy)
⇒ 273 = 13 × (x2 + y2 + xy)
⇒ x2 + y2 + xy = \(\frac{273}{13}\)
⇒ x2 + y2 + xy = 21 ............(i)
⇒ x2 + y2 - xy = 13 (given) .............(ii)
(i) - (ii),
⇒ 2xy = 8
⇒ xy = 4