If diagonals of a rhombus are 24 cm and 10 cm long, then its perimeter (in cm) is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 52
The diagonals of a rhombus bisect each other at right angles, so they cut the rhombus into four right triangles whose legs are half the diagonals and whose hypotenuse is a side.
Half the diagonals: \(24\div2=12\) cm and \(10\div2=5\) cm
Side \(=\sqrt{12^{2}+5^{2}}=\sqrt{144+25}=\sqrt{169}=13\) cm (Pythagoras’ theorem)
All four sides of a rhombus are equal, so perimeter \(=4\times13=52\) cm