A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by a value $5×10^{-8} T$ along Y-direction. The corresponding electric field is
(speed of light $c= 3 × 10^8\, m/s$)
Answer & explanation
Correct answer: option 1
Given:
Frequency $f = 25 \times 10^{9} \ \text{Hz}$
Magnetic field $B = 5 \times 10^{-8} \ \text{T}$
In vacuum, the relation between electric field and magnetic field is
$E = cB$
where $c = 3 \times 10^{8} \ \text{m/s}$.
$E = (3 \times 10^{8})(5 \times 10^{-8})$
$E = 15 \ \text{V/m}$
Answer: 15 V/m, along +X axis