Practicing Success
If n biscuits are distributed among N beggars, the probability that a particular beggar will get r(<n) biscuits, is |
$\frac{(N-1)^{n-r}}{N^n}$ $\frac{^nC_r}{N^{n-r}}$ $\frac{^nC_r(N-1)^{r}}{N^n}$ $\frac{^nC_r(N-1)^{n-r}}{N^n}$ |
$\frac{^nC_r(N-1)^{n-r}}{N^n}$ |
Since a biscuit can be given to any one of N beggars. Therefore, each biscuit can be distributed in N ways. So, the total number of ways of distributing n biscuits among N beggars is $N ×N×...×N=N^n $ n-times Now, r biscuits can be given to a particular beggar in ${^nC_r}$, ways and the remaining (n-r) biscuits can be distributed to (N-1) beggars in $(N-1)^{n-r}$ ways. Thus, the number of ways in which a particular beggar receives r biscuits is ${^nC}_r × (N-1)^{n-r}$ Hence, required probability $= \frac{^nC_r(N-1)^{n-r}}{N^n}$ |