What is the ratio of the mean proportional between 1.6 and 3.6 and the third proportional of 5 and 8?

3 : 16

Mean proportional between A and B = \(\sqrt {A\; \times\;B}\)

Mean proportional between 1.6 and 3.6 = \(\sqrt {1.6\; \times\; 3.6 }\) = 2.4

Third proportional of A and B = \(\frac{B\; \times\;B}{A}\)

Third proportional of 5 and 8 = \(\frac{8\;\times\;8}{5}\) = 12.8

Ratio = 2.4 : 12.8 = 3 : 16