Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

Find the mean proportion of \(\frac{1}{4}\) and \(\frac{1}{9}\) .

Options:

\(\frac{1}{5}\)

\(\frac{1}{6}\)

\(\frac{1}{7}\)

\(\frac{1}{8}\)

Correct Answer:

\(\frac{1}{6}\)

Explanation:

Mean proportion of a and b = \(\sqrt {a × b }\)

⇒ Mean proportion = \(\sqrt {\frac{1}{4} × \frac{1}{9}}\)

                               = \(\frac{1}{6}\)