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CUET
General Test
Quantitative Reasoning
Trigonometry
What is the value of $sec60^o + tan 45^o - sin^2 90^o$ ?
$\frac{2}{\sqrt{3}}$
$\frac{1}{\sqrt{3}}$
1
2
sec60º + tan45º - sin²90º
= 2 + 1 - 1
= 2