Practicing Success
Practicing Success
CUET Preparation Today
A capacitor of capacitance $C_1$ is charged upto V volt and then connected to an uncharged capacitor of capacity $C_2$. The final potential difference across each will be: |
$\frac{V}{\left(C_1+C_2\right)}$ $V$ $\frac{C_1 V}{\left(C_1+C_2\right)}$ $\frac{V}{2}$ |
$\frac{C_1 V}{\left(C_1+C_2\right)}$ |
The correct answer is Option (3) → $\frac{C_1 V}{\left(C_1+C_2\right)}$ |
