Practicing Success
Practicing Success
CUET Preparation Today
| Three numbers are chosen at random from numbers \(1\) to \(15\). The probability that they are consecutive is |
\(\frac{1}{15}\) \(\frac{2}{25}\) \(\frac{1}{35}\) \(\frac{1}{30}\) |
| \(\frac{1}{35}\) |
| Total cases \(=^{15}C_{3}\), Favourable cases \(=13\) |
