Three numbers are chosen at random from numbers \(1\) to \(15\). The probability that they are consecutive is1\(\frac{1}{15}\)2\(\frac{2}{25}\)3\(\frac{1}{35}\)4\(\frac{1}{30}\)Answer & explanation+Correct answer: option 3Total cases \(=^{15}C_{3}\), Favourable cases \(=13\)
