The figure shows how the molar conductivity (Λm) of aqueous solutions of CH3COOH and of KCl changes with c1/2.

For which of the two compounds can the limiting molar conductivity (Λ°m) be obtained by extending its plot to zero concentration, and why?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → KCl, because its plot is a straight line that can be extended to c1/2 = 0
Λ°m is the molar conductivity when the concentration approaches zero, so it can be read from a plot only when the plot can be extended to c1/2 = 0.
KCl (a strong electrolyte) gives a straight line: its Λm increases slowly with dilution. The line is extended to c1/2 = 0, and its intercept gives Λ°m.
\( \Lambda_m = \Lambda_m^{\circ} - A\,c^{1/2} \)
CH3COOH (a weak electrolyte) gives a curve that rises steeply near low concentrations, as its degree of dissociation increases on dilution. This curve cannot be extended to zero concentration, so its Λ°m is found by Kohlrausch law instead.
Why the other options are incorrect
Option (1) CH3COOH, because its Λm reaches the highest values near zero concentration — Incorrect. The high values come from the steep rise near zero concentration, and this steep rise is the reason the curve cannot be extrapolated.
Option (2) Both CH3COOH and KCl, because Λm of both increases on dilution — Incorrect. Λm of both increases on dilution, but only the KCl plot is a straight line that can be extended; the CH3COOH curve cannot.
Option (3) Neither of them, because Λm of both changes with concentration — Incorrect. A change with concentration does not prevent extrapolation: Λm of KCl changes in a straight line with c1/2, and the intercept of this line gives Λ°m.
NCERT (2026-27 edition):
Strong Electrolytes – “For strong electrolytes, Λm increases slowly with dilution and can be represented by the equation:”
\( \displaystyle \Lambda_m = \Lambda_m^{\circ} - A\,c^{1/2} \qquad (2.23) \)
“It can be seen that if we plot (Fig. 2.6) Λm against c1/2, we obtain a straight line with intercept equal to Λ°m and slope equal to ‘–A’.”
Weak Electrolytes – “Weak electrolytes like acetic acid have lower degree of dissociation at higher concentrations… In such cases Λm increases steeply (Fig. 2.6) on dilution, especially near lower concentrations. Therefore, Λ°m cannot be obtained by extrapolation of Λm to zero concentration.”

Fig. 2.6: Molar conductivity versus c½ for acetic acid (weak electrolyte) and potassium chloride (strong electrolyte) in aqueous solutions.