For any square matrix A of order n ≥ 2.
| List-I | List-II | ||
| (A) | $|A^{-1}|,$ if A is invertible | (I) | $|A|^{n-1}$ |
| (B) | |adj A| | (II) | $|A|^{(n-1)^2}$ |
| (C) | |adj (adj A)| | (III) | $\frac{1}{|A|}$ |
| (D) | A(adj A) | (IV) | $|A|I$ |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(III), (B)-(I), (C)-(II),(D)-(IV)
| List-I | List-II | ||
| (A) | $|A^{-1}|,$ if A is invertible | (III) | $\frac{1}{|A|}$ |
| (B) | |adj A| | (I) | $|A|^{n-1}$ |
| (C) | |adj (adj A)| | (II) | $|A|^{(n-1)^2}$ |
| (D) | A(adj A) | (IV) | $|A|I$ |