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If x + \(\frac{1}{x}\) = 21 then find the value of x2 + \(\frac{1}{x^2}\) |
441 439 443 291 |
439 |
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 21, then ⇒ x2 + \(\frac{1}{x^2}\) = 212 - 2 = 439 |
