Practicing Success
Practicing Success
CUET Preparation Today
If x + \(\frac{1}{x}\) = 21 then find the value of x2 + \(\frac{1}{x^2}\) |
441 439 443 291 |
439 |
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 Here, x + \(\frac{1}{x}\) = 21, then ⇒ x2 + \(\frac{1}{x^2}\) = 212 - 2 = 439 |
