A is 40 % more efficient than B. How much time will both, working together, take to finish the work, which B alone can finish in 36 days?
Answer & explanation
Correct answer: option 3
A is 40% more efficient than B i.e;
\(\frac{A}{B}\) = \(\frac{140}{100}\) = \(\frac{7}{5}\)
⇒ Efficiency (A = 7, B = 5),
B finishes work in 36 days
therefore, total work = 5 x 36 = 180 .. (Efficiency × Days = Total work)
⇒ Time taken to complete the work by working together = \(\frac{180}{7+5}\) =
\(\frac{180}{12}\) = 15 days.