Doppler shift for the light of wavelength 6000 Å emitted from the sun is 0.04 Å. If radius of the sun is 7 × 108 m then time period of rotation of the sun will be
Answer & explanation
Correct answer: option 4
$ \text{ doppler shift } d\lambda = \frac{v}{c} \lambda = \frac{2\pi R}{T} \frac{\lambda}{c}$
$ T = \frac{2\pi R \lambda}{d\lambda c} = 25days$