The radius of a circle is equal to length of the rectangle. The circumference of the circle and breadth of the rectangle is 132 cm and 20 cm respectively. The diagonal of the rectangle is:(Take $π =\frac{22}{7}$)

29 cm

We know that,

Circumference of the rectangle = 2πr

Diagonal of rectangle = (length)² + (breadth)²

Given,

Circumference = 132 cm

 Breadth = 20 cm

So, 2 πr = 132

= 2 × \(\frac{22}{7}\)× r = 132

= r = 132 × \(\frac{7}{22}\)× \(\frac{1}{2}\) = 21 cm

We know the length = radius

Then, diagonal of the rectangle

= d² = l² + b²

= d² = 21² + 20²

= d² = 441 + 400

= d = \(\sqrt {841}\) = 29 cm