A proton and an alpha particle have the same de-Broglie's wavelength. What is same for both of them? |
Velocity Energy Charge Momentum |
Momentum |
The correct answer is Option (4) → Momentum De Broglie wavelength, $λ=\frac{h}{P}$ where P is momentum and h = Planck Constant ∴ if $λ_1=λ_2$ [given] then ⇒ $P_1=P_2$ ⇒ Momentum is same for both |