A proton and an alpha particle have the same de-Broglie's wavelength. What is same for both of them?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Momentum
De Broglie wavelength, $λ=\frac{h}{P}$
where P is momentum and h = Planck Constant
∴ if $λ_1=λ_2$ [given]
then ⇒ $P_1=P_2$ ⇒ Momentum is same for both