Practicing Success
If the dimensions of a physical quantity are given by $M^aL^bT^c$ , then the physical quantity will be |
Force if a =0 , b= 0 , c = -1 Energy if a =1 , b= 1 , c = -2 Momentum if a =0 , b= -1 , c = -2 Power if a =1 , b= 2 , c = -3 |
Power if a =1 , b= 2 , c = -3 |
Force = $[MLT^{-2}]$ so a = 1, b = 1, c = -2 Energy = $[ML^2T^{-2}]$ so a = 1, b = 2, c = -2 Momentum = $[ML^2T^{-1}]$ so a = 1, b = 2, c = -1 Power = $\frac{[Energy]}{[Time]}= [ML^2T^{-3}]$ so a = 1, b = 2, c = - 3 |