Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

If the dimensions of a physical quantity are given by $M^aL^bT^c$ , then the physical quantity will be

Options:

Force if a =0 , b= 0 , c = -1

Energy if a =1 , b= 1 , c = -2

Momentum if a =0 , b= -1 , c = -2

Power if a =1 , b= 2 , c = -3

Correct Answer:

Power if a =1 , b= 2 , c = -3

Explanation:

Force = $[MLT^{-2}]$ so a = 1, b = 1, c = -2

Energy = $[ML^2T^{-2}]$ so a = 1, b = 2, c = -2

Momentum = $[ML^2T^{-1}]$ so a = 1, b = 2, c = -1

Power = $\frac{[Energy]}{[Time]}= [ML^2T^{-3}]$ so a = 1, b = 2, c = - 3