If the dimensions of a physical quantity are given by $M^aL^bT^c$ , then the physical quantity will be
Answer & explanation
Correct answer: option 4
Force = $[MLT^{-2}]$ so a = 1, b = 1, c = -2
Energy = $[ML^2T^{-2}]$ so a = 1, b = 2, c = -2
Momentum = $[ML^2T^{-1}]$ so a = 1, b = 2, c = -1
Power = $\frac{[Energy]}{[Time]}= [ML^2T^{-3}]$ so a = 1, b = 2, c = - 3