If $k^4+\frac{1}{k^4}=194$, then what is the value of $k^3+\frac{1}{k^3}$?
Answer & explanation
Correct answer: option 2
If x4 + \(\frac{1}{x^4}\) = a
then x2 + \(\frac{1}{x^2}\) = \(\sqrt {a + 2}\) = b
and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)
$k^4+\frac{1}{k^4}=194$
$k^3+\frac{1}{k^3}$ = ?
k2 + \(\frac{1}{k^2}\) = \(\sqrt {194 + 2}\) = 14
and k + \(\frac{1}{k}\) = \(\sqrt {14 + 2}\) = 4
$k^3+\frac{1}{k^3}$ = 43 - 4 × 3 = 52