A thief is spotted by a policeman from a distance of 250 m. When the policeman starts the chase, the thief also starts running. Assuming that the speed of the thief is 10 km/h and that of the policeman is 12 km/h, how far would the thief have run before he is caught?
Answer & explanation
Correct answer: option 2
Relative speed of thief and policeman = 12 - 10 = 2km/h
( whn moves in same direction )
2 km/h = \(\frac{5}{9}\) m/sec
Time = \(\frac{Distance }{Speed }\)
= \(\frac{250 × 9 }{5 }\)
= 450 sec
Distance covered by Thief before he was caught =
= 10 × \(\frac{5}{18}\) ×450
= 1250 m
= 1.25 km