A thief is spotted by a policeman from a distance of 250 m. When the policeman starts the chase, the thief also starts running. Assuming that the speed of the thief is 10 km/h and that of the policeman is 12 km/h, how far would the thief have run before he is caught?

1.25 km

Relative speed of thief and policeman = 12 - 10 = 2km/h

( whn moves in same direction )

2 km/h = \(\frac{5}{9}\) m/sec

Time = \(\frac{Distance }{Speed }\)

= \(\frac{250 × 9 }{5 }\)

= 450 sec

Distance covered by Thief before he was caught =

= 10  × \(\frac{5}{18}\) ×450

= 1250 m

= 1.25 km