What is the overall order of the reaction?

Rate = $k[A]^{1/2}[B]^{3/2}$

2

The correct answer is Option (1) → 2.

To determine the overall order of the reaction from the rate law, we can analyze the rate expression given:

\(\text{Rate} = k[A]^{1/2}[B]^{3/2}\)

Step 1: Identify the Orders with Respect to Each Reactant

For \([A]\): The exponent is \( \frac{1}{2} \). Thus, the order with respect to \( A \) is \( \frac{1}{2} \).

For \([B]\): The exponent is \( \frac{3}{2} \). Thus, the order with respect to \( B \) is \( \frac{3}{2} \).

Step 2: Calculate the Overall Order

The overall order of the reaction is the sum of the individual orders:

\(\text{Overall Order} = \text{Order with respect to } A + \text{Order with respect to } B\)

Substituting the values we found:

\(\text{Overall Order} = \frac{1}{2} + \frac{3}{2} = \frac{1}{2} + \frac{3}{2} = \frac{4}{2} = 2\)

Thus, the overall order of the reaction is 2.