Match LIST I with LIST II
|
LIST I |
LIST II |
|
A. \([Co(NH_3)_4Cl_2]^+\) |
I. Optical |
| B. \(cis-[Co(en)_2Cl_2]\) | II. Ionization |
| C. \([Co(NH_3)_5SO_4]Br\) | III. Coordination |
| D. \([Co(NH_3)_6][Cr(CN)_6]\) | IV. Geometrical |
Choose the correct answers from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → A-IV, B-I, C-II, D-III
Isomers of coordination compounds are of two kinds. Stereoisomers (geometrical, optical) have the same bonds but a different arrangement in space. Structural isomers (linkage, coordination, ionisation, solvate) have different bonds.
(A) [Co(NH3)4Cl2]+ — This matches (IV) Geometrical. It is an octahedral MA4B2 complex; the two Cl ligands can be next to each other (cis) or opposite each other (trans).
(B) cis-[Co(en)2Cl2] — This matches (I) Optical. The cis form has no plane of symmetry, so it exists as two non-superimposable mirror images.
(C) [Co(NH3)5SO4]Br — This matches (II) Ionization. The counter ion can change places with a ligand, giving \( \ce{[Co(NH3)5Br]SO4} \); the two give different ions in solution.
(D) [Co(NH3)6][Cr(CN)6] — This matches (III) Coordination. Both ions are complexes, and the ligands can be interchanged between the two metals, as in \( \ce{[Cr(NH3)6][Co(CN)6]} \).