A coil has an inductance of 0.02 H and the current is increasing at the rate of 200 A/s. The emf induced in it, is

-4 V

The correct answer is Option (2) → -4 V

Given: $L = 0.02\,\text{H}$, $\frac{dI}{dt} = 200\,\text{A/s}$

Induced emf in a coil: $\mathcal{E} = - L \frac{dI}{dt}$

Substitute values: $\mathcal{E} = - 0.02 \cdot 200 = -4\,\text{V}$

Answer: $\mathcal{E} = -4\,\text{V}$