Practicing Success
Practicing Success
CUET Preparation Today
A and B each throw a fair dice. The probability that A’s throw is not greater than B’s throw, is equal to |
$\frac{1}{3}$ $\frac{2}{3}$ $\frac{7}{12}$ $\frac{5}{12}$ |
$\frac{7}{12}$ |
Let ‘A’s throw is r,r = 1, 2, 3, …6, then ‘B’s outcome can be (r, r + 1, ….6), Thus required probability $=\sum\limits_{r=1}^6 \frac{7-r}{36}=\sum\limits_{r=1}^6 \frac{r}{36}=\frac{7}{12}$ |
