Three brothers divided Rs.1040 among them in such a way that the share of the second is equal to \(\frac{2}{11}\) of the other two. Find the share of the second one.

160

                   A + C     :           B

  Shares →      11       :           2

Total amount = 1040

 11x + 2x = 1040

 x = \(\frac{1040}{13}\)

 2x = \(\frac{1040}{13}\) × 2 = 160