The value of $tan^{-1}1+cos^{-1}\left(-\frac{1}{2}\right)+sin^{-1}\left(-\frac{1}{2}\right)$ is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{3\pi}{4}$
$\tan^{-1}1+\cos^{-1}\left(-\frac{1}{2}\right)+\sin^{-1}\left(-\frac{1}{2}\right)$
$=\frac{π}{4}+π-\frac{π}{3}-\frac{π}{6}=-\frac{π}{4}+-\frac{π}{2}$
$=\frac{3π}{4}$