The value of $tan^{-1}1+cos^{-1}\left(-\frac{1}{2}\right)+sin^{-1}\left(-\frac{1}{2}\right)$ is

$\frac{\pi}{4}$ $\frac{\pi}{2}$ $\frac{3\pi}{4}$ $\pi $

$\frac{3\pi}{4}$

The correct answer is Option (3) → $\frac{3\pi}{4}$ $\tan^{-1}1+\cos^{-1}\left(-\frac{1}{2}\right)+\sin^{-1}\left(-\frac{1}{2}\right)$ $=\frac{π}{4}+π-\frac{π}{3}-\frac{π}{6}=-\frac{π}{4}+-\frac{π}{2}$ $=\frac{3π}{4}$