Three pizza outlets A, B and C sell three types of pizza namely cheese pizza, veg pizza and paneer pizza. In a day, A can sell 40 cheese pizza, 30 veg pizza and 20 paneer pizza; B can sell 20 cheese pizza, 40 veg pizza and 60 paneer pizza; C can sell 60 cheese pizza, 20 veg pizza and 30 paneer pizza. If the revenue generated in a day by A is ₹6000, by B is ₹9000 and by C is ₹7000. If x denotes selling price of cheese pizza, y is selling price of veg pizza and z be the selling price of Paneer pizza then based on this information, answer the following question:

The matrix representation of the above problem is :

$\left[\begin{array}{lll}4 & 3 & 2 \\ 1 & 2 & 3 \\ 6 & 2 & 3\end{array}\right]\left[\begin{array}{l}\mathrm{x} \\ \mathrm{y} \\ \mathrm{z}\end{array}\right]=\left[\begin{array}{c}600 \\ 450 \\ 700\end{array}\right]$

Outlet A

40x + 30y + 20z = 6000 ⇒ 4x + 3y + 2z = 600

Outlet B

20x + 40y + 60x = 9000 ⇒ x + 2y + 3x = 450

Outlet C

60x + 20y + 30z = 7000 ⇒ 6x + 2y + 3z = 700

So, the matrix representation will be:

$\left[\begin{array}{lll}4 & 3 & 2 \\ 1 & 2 & 3 \\ 6 & 2 & 3\end{array}\right]\left[\begin{array}{l}\mathrm{x} \\ \mathrm{y} \\ \mathrm{z}\end{array}\right]=\left[\begin{array}{c}600 \\ 450 \\ 700\end{array}\right]$