If cot A = k, then sin A is equal to :
(presume that A is an acute angle)
Answer & explanation
Correct answer: option 1
cot A = k
{ cot A = \(\frac{B }{P}\) }
By pythagoras theorem,
P² + B² = H²
1² + k² = H²
H = \(\sqrt { 1 + k² }\)
Now,
sinA
= \(\frac{P }{H}\)
= \(\frac{1 }{ \sqrt { 1 + k² }\}\)