At what height the gravitational field reduces by 75% the gravitational field at the surface of earth ?
Answer & explanation
Correct answer: option 1
$\left(g-\frac{3 g}{4}\right)=\frac{g R^2}{(R+h)^2}$
⇒ h = R
At what height the gravitational field reduces by 75% the gravitational field at the surface of earth ?
Correct answer: option 1
$\left(g-\frac{3 g}{4}\right)=\frac{g R^2}{(R+h)^2}$
⇒ h = R