If sec 3x = cosec (3x - 30°) where 3x is an acute angle find the value of 2x.
Answer & explanation
Correct answer: option 2
We know that if sec A = cosec B, then A + B = 90°
ATQ,
sec 3x = cosec (3x - 30°)
⇒ 3x + 3x - 30° = 90°
⇒ 6x = 120°
⇒ 2x = 40°
If sec 3x = cosec (3x - 30°) where 3x is an acute angle find the value of 2x.
Correct answer: option 2
We know that if sec A = cosec B, then A + B = 90°
ATQ,
sec 3x = cosec (3x - 30°)
⇒ 3x + 3x - 30° = 90°
⇒ 6x = 120°
⇒ 2x = 40°