If sec 3x = cosec (3x - 30°) where 3x is an acute angle find the value of 2x.

60° 40° 35° 30°

40°

We know that if sec A = cosec B, then A + B = 90° ATQ, sec 3x = cosec (3x - 30°) ⇒ 3x + 3x - 30° = 90° ⇒ 6x = 120° ⇒ 2x = 40°