Arrange the following series of emission lines in the spectrum of hydrogen atom in sequence according to their increasing wavelengths
(A) Paschen series
(B) Lyman series
(C) Balmer series
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (B), (C), (A)
Hydrogen atom series wavelengths:
- Lyman series (transitions to n=1): UV region → shortest wavelength
- Balmer series (transitions to n=2): Visible region → intermediate wavelength
- Paschen series (transitions to n=3): Infrared region → longest wavelength
∴ Increasing wavelength sequence: Lyman < Balmer < Paschen