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The total surface area of a regular tetrahedron with each edge of length √3 cm is - |
6√3 cm² 4√3 cm² 3√3 cm² 27 cm² |
3√3 cm² |
T.S.A. of a tetrahedron = 4 × \(\frac{(\sqrt {3})}{4}\) × (edge)2 = \(\sqrt {3}\)a2 = \(\sqrt {3}\) (\(\sqrt {3}\))2 = 3\(\sqrt { 3}\) cm2 |
