Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

A 50 Ω resistance and an inductance of $\frac{2}{3 \pi} H$ are connected in series with power supply of 220 Volt AC of 50 Hz. Choose the correct statement:

Options:

Current leads the potential difference by $\tan ^{-1}\left(\frac{3}{4}\right)$

Potential difference leads the current by $90^{\circ}$

Current leads the potential difference by $\tan ^{-1}\left(\frac{4}{3}\right)$

Potential difference leads the current by $\tan ^{-1}\left(\frac{4}{3}\right)$

Correct Answer:

Potential difference leads the current by $\tan ^{-1}\left(\frac{4}{3}\right)$

Explanation:

$X_L = \omega L = 2\pi f L = \frac{200}{3}$

$\Rightarrow \phi = tan^{-1}\frac{X_L}{R} =  tan^{-1}\frac{4}{3}$

Potential lead the current