CUET Preparation Today
A 50 Ω resistance and an inductance of $\frac{2}{3 \pi} H$ are connected in series with power supply of 220 Volt AC of 50 Hz. Choose the correct statement: |
Current leads the potential difference by $\tan ^{-1}\left(\frac{3}{4}\right)$ Potential difference leads the current by $90^{\circ}$ Current leads the potential difference by $\tan ^{-1}\left(\frac{4}{3}\right)$ Potential difference leads the current by $\tan ^{-1}\left(\frac{4}{3}\right)$ |
Potential difference leads the current by $\tan ^{-1}\left(\frac{4}{3}\right)$ |
The correct answer is Option (4) → Potential difference leads the current by $\tan ^{-1}\left(\frac{4}{3}\right)$ Given, f, frequency = 50Hz L, inductance = $\frac{2}{3\pi}=Hz$ ∴ Inductive inductance $(X_L) = 2\pi f L$ $=2\pi ×50×\frac{2}{3\pi}=\frac{200}{3}$ $\Rightarrow \phi = tan^{-1}\frac{X_L}{R} = tan^{-1}\frac{4}{3}$ |
