A 50 Ω resistance and an inductance of $\frac{2}{3 \pi} H$ are connected in series with power supply of 220 Volt AC of 50 Hz. Choose the correct statement:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Potential difference leads the current by $\tan ^{-1}\left(\frac{4}{3}\right)$
Given,
f, frequency = 50Hz
L, inductance = $\frac{2}{3\pi}=Hz$
∴ Inductive inductance $(X_L) = 2\pi f L$
$=2\pi ×50×\frac{2}{3\pi}=\frac{200}{3}$
$\Rightarrow \phi = tan^{-1}\frac{X_L}{R} = tan^{-1}\frac{4}{3}$