The average of first 99 positive integers is:
Answer & explanation
Correct answer: option 2
Average of first n positive integers = \(\frac{n\;+\;1}{2}\)
Average of first 99 positive integers = \(\frac{99\;+\;1}{2}\) = 50
The average of first 99 positive integers is:
Correct answer: option 2
Average of first n positive integers = \(\frac{n\;+\;1}{2}\)
Average of first 99 positive integers = \(\frac{99\;+\;1}{2}\) = 50