If $f(x)=3 x^2+10 x-5$, then by using differentials the appropriate value of f(2.03) is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) - 27.66
$f(2)=3×4+10×2-5=27$
$f'(x)=6x+10$
so $f(2.03)=f(2)+\left.\frac{df(x)}{dx}\right]_{x=2}×Δx$
$=27+(22)×0.03$
$=27.66$