CUET Preparation Today
If $f(x)=3 x^2+10 x-5$, then by using differentials the appropriate value of f(2.03) is |
37.66 47.66 17.66 27.66 |
27.66 |
The correct answer is Option (4) - 27.66 $f(2)=3×4+10×2-5=27$ $f'(x)=6x+10$ so $f(2.03)=f(2)+\left.\frac{df(x)}{dx}\right]_{x=2}×Δx$ $=27+(22)×0.03$ $=27.66$ |
