A short bar magnet of magnetic dipole moment $10^{-5} A\, m^2$ is kept in a uniform magnetic field $3×10^{-4}T$ at an angle of 30°. The torque acting on it is:

$1.5×10^{-9} Nm$ $3×10^{-9} Nm$ $1.5×10^{-5} Nm$ $3×10^{-5} Nm$

$1.5×10^{-9} Nm$

The correct answer is Option (1) → $1.5×10^{-9} Nm$